Counting diagonals

The question

A polygon has 14 sides.

How many diagonals does it have?

The same count, minus the ones already joined

corners:14
14×13=182
182÷2=91
all lines:91· already joined:14
91−14=77
  1. There are 14 of them, and each already has two neighbors.
  2. First join every pair of the 14, neighbors included. Each corner reaches 13 others, so that is 14 × 13 = 182 — but each line was counted from both ends, so halve it: 182 ÷ 2 = 91.
  3. But 14 of them are its sides, joining each corner to its neighbors, and those are not being asked about.
  4. Take them off to leave the diagonals that cut across: 91 − 14 = 77.

How it works.

  1. 01

    There are 14 of them, and each already has two neighbors.

  2. 02

    First join every pair of the 14, neighbors included. Each corner reaches 13 others, so that is 14 × 13 = 182 — but each line was counted from both ends, so halve it: 182 ÷ 2 = 91.

  3. 03

    But 14 of them are its sides, joining each corner to its neighbors, and those are not being asked about.

  4. 04

    Take them off to leave the diagonals that cut across: 91 − 14 = 77.