The smudged sum

The question

This sum was photocopied badly and two digits came out blank: 4■ + ■9 = 67.

What were the two numbers?

The ten the ones column sends across

4■+■9=67
8+9=17
4+1=5
without the ten:29
48+19=67
  1. Two digits are covered. Start with the ones column.
  2. The ones column settles on its own: something and 9 has to end in 7, and 8 + 9 = 17. So the first covered digit is 8.
  3. But 17 does not fit in one column. A ten goes across, so the tens column starts at 4 + 1 = 5.
  4. Forget that ten and you would get 2 — ten too many.
  5. With it, the tens column is 5 + 1 = 6, so the other covered digit is 1: the two numbers are 48 and 19.

How it works.

  1. 01

    Two digits are covered. Start with the ones column.

  2. 02

    The ones column settles on its own: something and 9 has to end in 7, and 8 + 9 = 17. So the first covered digit is 8.

  3. 03

    But 17 does not fit in one column. A ten goes across, so the tens column starts at 4 + 1 = 5.

  4. 04

    Forget that ten and you would get 2 — ten too many.

  5. 05

    With it, the tens column is 5 + 1 = 6, so the other covered digit is 1: the two numbers are 48 and 19.